1. I feel the need to explain things first before I write the numeric value.
Let x be the total number of students in the school. 25% of this value is given to be 35.
(0.25)x = 35
The value of x is 140. 75% of this value is the answer which is equal to 105.
2. Let y be the alternative schools. With this, the number of charter schools is 2x - 6 which is equal to 52
2x - 6 = 52
The value of x is 29. Therefore, there are 29 charter schools.
x makes a linear pair with 120 degrees, so is supplementary:
Answer: 60 degrees
Answer:
B, E
Step-by-step explanation:
The equation of that line in slope intercept form is y = -2/5x + 2
The slope of a line parallel to that line will be the same as its slope, so -2/5.
To find the y-intercept of a line that passes through the point (-5, 1) with that slope, you will have to plug in the x and y values of that point into what you know of the equation of the line.
y = -2/5x + b
1 = -2/5(-5) + b
1 = 2 + b
-1 = b
From this, you can construct an equation.
y = -2/5x - 1
However, this is not an answer choice.
It cannot be A because this line does not have a slope of -1.
2x + 5y = 15
5y = -2x - 5
y = -2/5x - 1
It can be B because this line is the same as the equation we came up with.
It cannot be C because this line does not have a slope of -1 or a y-intercept of -3.
2x + 5y = -15
5y = -2x - 15
y = -2/5x - 3
It cannot be D because this line does not have a y-intercept of -3.
y - 1 = -2/5(x + 5)
y - 1 = -2/5x - 2
y = -2/5x - 1
It can be E because this equation matches the one we came up with.
Answer:
0.01596
Step-by-step explanation:
A scientist claims that 8% of the viruses are airborne
Given that:
The population proportion p = 8%
The sample size = 477
We can calculate the standard deviation of the population proportion by using the formula:
![\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_p%20%3D%20%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
![\sigma_p = \sqrt{\dfrac{0.8(1-0.8)}{477}}](https://tex.z-dn.net/?f=%5Csigma_p%20%3D%20%5Csqrt%7B%5Cdfrac%7B0.8%281-0.8%29%7D%7B477%7D%7D)
![\sigma_p = \sqrt{\dfrac{0.0736}{477}}](https://tex.z-dn.net/?f=%5Csigma_p%20%3D%20%5Csqrt%7B%5Cdfrac%7B0.0736%7D%7B477%7D%7D)
![\sigma_p = 0.02098](https://tex.z-dn.net/?f=%5Csigma_p%20%3D%200.02098)
The required probability can be calculated as:
![P(| \hat p - p| > 0.03) = P(\hat p - p< -0.03 \ or \ \hat p - p > 0.03)](https://tex.z-dn.net/?f=P%28%7C%20%5Chat%20p%20-%20p%7C%20%3E%20%200.03%29%20%3D%20P%28%5Chat%20p%20-%20p%3C%20-0.03%20%5C%20or%20%5C%20%20%5Chat%20p%20-%20p%20%3E%200.03%29)
![= P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} < -\dfrac{0.03}{0.0124} \bigg ) + P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} >\dfrac{0.03}{0.0124} \bigg )](https://tex.z-dn.net/?f=%3D%20P%20%5Cbigg%20%28%20%5Cdfrac%7B%5Chat%20p%20-p%20%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%3C%20-%5Cdfrac%7B0.03%7D%7B0.0124%7D%20%20%5Cbigg%20%29%20%2B%20%20P%20%5Cbigg%20%28%20%5Cdfrac%7B%5Chat%20p%20-p%20%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%3E%5Cdfrac%7B0.03%7D%7B0.0124%7D%20%5Cbigg%20%29)
= P(Z < -2.41) + P(Z > 2.41)
= P(Z < -2.41) + P(Z < -2.41)
= 2P( Z< - 2.41)
From the Z-tables;
= 2 ( 0.00798
= 0.01596
Thus, the required probability = 0.01596
Answer:
The adjusting entry for office supplies on March 31 is:
Dr Cr
Supplies Expense 250
Office Supplies 250
Step-by-step explanation:
850+450-1,050 = $250
Beginning Supplies $ 850
Add:Purchase during the month $450
Total Supplies Available $ 1,300
Less: Ending Supplies in hand $ 1,050
Supplies Expenses for March $ 250