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slamgirl [31]
3 years ago
5

Why dont people answer the questions i post :)

Mathematics
2 answers:
Vadim26 [7]3 years ago
6 0

Answer:

idk but good luck :)

Step-by-step explanation:

N76 [4]3 years ago
4 0

Answer:

cuz your questions are hard

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Evaluate the expression when c = -6 And y = 7<br><br> y - 9c
GrogVix [38]
The answer is 61. hope that help.
5 0
3 years ago
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Write an equation: the quotient of r and 258 is q
dedylja [7]
258 divided by r = q
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3 years ago
Mick paid $2.94 in sales tax of an item that cost $42.00 before tax. At that rate, how much would he pay in sales tax for an ite
BabaBlast [244]
$4.06
2.94/42=7/100
4.06/58=7/100
7 0
2 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Using the right triangle below. What is the name for side AC ?
irga5000 [103]

Answer:

B) Adjacent

Step-by-step explanation:

The hypotenuse will ALWAYS be designated as the longest side in a right triangle.

Pretend that the angle (the one with the round line) is an eyeball that is looking outwards. The eye is looking out at side BC. That means that line BC is opposite of the angle.

This leaves one side left: the adjacent side. The adjacent side is the side next to the angle. But it is the side that is NOT the hypotenuse.

4 0
2 years ago
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