The equation of line passing through (0, 6) and (6, 0) is y = -x + 6
<u><em>Solution:</em></u>
Given that graph of a line passes through the points (0, 6) and (6, 0)
<em><u>The equation of line containing two points is given as:</u></em>
----- eqn 1
Where "m" is the slope of line
Here given two points are (0, 6) and (6, 0)

Let us first find the slope of line

Substituting the values we get,

Thus slope of line "m" = -1
Substituting in eqn 1

In standard form we get,
y = -x + 6
x + y = 6
Thus equation of line is found
Answer: if you using edg it’s -9
Step-by-step explanation:
Answer:
5x - 2y = -2
Step-by-step explanation:
Slope: 5/2 and (-2,-4)
y-intercept= -4-(5/2)(-2) = 1
y = 5/2x+ 1
5/2x - y = - 1
2(5/2x - y) = -1*2
5x - 2y = - 2
Answer:
The equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

Step-by-step explanation:
The point-slope form of the equation of a line is:

where
-
is the slope of the line and, -
is a point on the line.
As the slope is
, and the point is 
so
Equation of the line will be:

Further simplifying


Therefore, the equation of the line that passes through the point (3,-3) and has a slope of 0 will be:

The answer is 4 cm I think idk