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Black_prince [1.1K]
3 years ago
11

If there are n boys and n girls in the class, what is the probability that all of the randomly chosen pairs of dancing partners

will consist of a boy and a girl?

Mathematics
1 answer:
ladessa [460]3 years ago
5 0

The solution is in the attachment

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Select all the correct answers.
blsea [12.9K]
#4 a reflection across the x-axis is the only correct answer , the other ones aren’t correct .
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What is the difference? <br> 4/3-7/9
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Answer:

Step-by-step explanation:

4/3-7/9=12/9-7/9=5/9.

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A box of colored pencils cost $4.50 if there are 40 pencils how much would 60 pencils cost
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6.75

Step-by-step explanation:

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3 years ago
What is 1928912 times 192 divided by 182 times 9 plus 4 - 12378923789 times -52?
qaws [65]
(1928912×192) ÷ (182×9) + 4- (12378923789×-52)

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3 0
3 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
2 years ago
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