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jeka57 [31]
3 years ago
10

The measure of two supplementary angels, s and t, are the ratio of 7:3. Find the value of s

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

b 45 degrease

Step-by-step explanation:

i took the test yolo

Andrews [41]3 years ago
6 0

7x+3x=180

10x=180

/10     /10

x=18

7x=s

7(18)=126

3x=t

3(18)=t

54=t

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Solve the following equation for the variable a. 2a+b=c-4d
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Drag the tiles to list the sides of △MNO from shortest to longest.
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The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

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a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

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a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

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Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

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