All categories

3 years ago

How do you solve this equation? 5-3z-18= z-1+ 8z Thanks

2 answers:

7 0

First, you have to combine like terms so -13-3z=9z-1 ; Then you have to do the variables so -13=12z-1 or -13-12z=-1 ; Next, you have to do the constant numbers so -12=12z or 12z=-12 ; Finally you divide so -12/12z = z=-1

rodikova [14]3 years ago

3 0

5-3z-18=z-1+8z
Add like terms
-13-3z=9z-1
Move terms
-12z=12
Divide both sides by 12
z=1

You might be interested in

21. What is the simplified form of the following expression? (1 point)

Andre45 [30]

Answer (6y – 42)

6(y – 7)

Explanation:

5 0

3 years ago

If 60% of a KNOWN NUMBER is 180, what is the 40% of that UNKNOWN NUMBER?

Lana71 [14]

Step-by-step explanation:

I think you mean you want to find out 40% of a number,, when 60% of it is 180, so I'll answer that:

60% = 180

÷6

10% = 30

40% = 120

(if you want to find 100%, multiply 30 by 10)

Hopefully this helps :)

4 0

2 years ago

On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).

Valentin [98]

Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

Use distance formula.

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

~ Put all values.

$d = \sqrt{ {( - 4 + 4)}^{2} + ( { - 10 + 4)}^{2} }$

~ Simplify it.

$d = \sqrt{ {0}^{2} + ( { - 6)}^{2} }$

$d = \sqrt{36}$

Therefore, distance between the points is 6 units.

Hope it helps...

6 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

Can someone help with this question below?

Oxana [17]

Answer:

C = 106.76 cm

Step-by-step explanation:

In the diagram, we are given the diameter (d), which is 34 cm. Using the formula you are given, we know circumference is 3.14 × d

C = 3.14 × d

C = 3.14 × (34)

C = 106.76 cm

The circumference is around 106.76 cm

6 0

3 years ago

Read 2 more answers