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3 years ago

12x+40=15x+25 solve for x

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Answer:

x=5

Step-by-step explanation:

12x+40=15x+25

12x=15x-15

12x=15x-15-15x

-3x=-15

-3x=-15 divide both by -3

answer is 5

fiasKO [112]3 years ago

6 0

Answer:

5 = x

Step-by-step explanation:

12x+40=15x+25

Subtract 12x from each side

12x-12x+40=15x-12x+25

40 = 3x +25

Subtract 25 from each side

40-25 = 3x+25-25

15 =3x

Divide by 3

15/3 =3x/3

5 = x

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Read 2 more answers

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

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