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inysia [295]
3 years ago
11

Graph each exponential function Y=4x

Mathematics
1 answer:
jeka943 years ago
5 0
<span>ahh okay i was going to say...thats a straight line haha....okay well lets see....what is 4^0? 1 right? what is 4^1? 4 ...4^2? 16 ...4^3? 64....make a graph with those points</span>
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What’s the answer to 10(x-2)-3 (x+3)
Svetlanka [38]

Answer:7x-29

Step-by-step explanation: simplify and open the brackets.remember that a letter and a number cannot be sumed up but can my multipled together

5 0
3 years ago
D. Evaluate each of the following. (5 points)
Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer:  5/2

============================================

Problem 3

(f o f o f)(1) = f(  f(f(1)) )

(f o f o f)(1) = f(  (f o f)(1) )

(f o f o f)(1) = f(  5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f(   f(f(f(1))   )

(f o f o f o f)(1) = f(   (f o f o f)(1)    )

(f o f o f o f)(1) = f(   29/10   )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f(   f(f(f(f(1))))   )

(f o f o f o f o f)(1) = f(   (f o f o f o f)(1)  )

(f o f o f o f o f)(1) = f(   941/290  )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0
3 years ago
Read 2 more answers
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
The sum of a and 8<br> Shjdjjdjkdkdjdkd
katrin [286]

Answer:

a+8

Step-by-step explanation:

"sum" tells you to add the two numbers together.

8 0
4 years ago
Find the volume of each sphere to the nearest hundredth?​
Alenkinab [10]

Answer:

Can i have a diagram please

Step-by-step explanation:

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