All categories

3 years ago

Graph each exponential function Y=4x

1 answer:

jeka943 years ago

5 0

<span>ahh okay i was going to say...thats a straight line haha....okay well lets see....what is 4^0? 1 right? what is 4^1? 4 ...4^2? 16 ...4^3? 64....make a graph with those points</span>

You might be interested in

What is the measure of angle 4??? please help asap!!!

ArbitrLikvidat [17]

<h3>Answer: 80 degrees</h3>

===========================================================

Explanation:

Angle 3 and the 100 degree angle are corresponding angles. They are both in the southeast quadrant of their four-corner angle configuration. Assuming the lines that look horizontal are parallel, this would mean angle 3 is 100 degrees. Recall that corresponding angles are congruent when we have parallel lines.

Once we know that angle 3 = 100, we will use this to find angle 4.

Angles 3 and 4 add to 180. They form a straight angle or straight line.

(angle3)+(angle4) = 180

(100) + (angle4) = 180

angle4 = 180-100

angle4 = 80 degrees

7 0

2 years ago

Read 2 more answers

8 pencils cost 72p how much is the cost of 1.

Gala2k [10]

The cost will be 9 for 1 pencial

8 0

3 years ago

Read 2 more answers

Find the square of ( b - 9 )

Kruka [31]

Answer:

${b}^{2} - 18b + 81$

Step-by-step explanation:

${(b - 9)}^{2} = {b}^{2} - 2 \times b \times 9 + {(9)}^{2} \\ = {b}^{2} - 18b + 81$

6 0

3 years ago

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?

KIM [24]

Answer:

The answer is

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$tan(\theta)=-1$

Step-by-step explanation:

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin^{2}(\theta)+cos^{2}(\theta)=1$

In this problem we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

$\frac{3\pi}{2}$

The angle $\theta$ belong to the third or fourth quadrant

The value of $sin(\theta)$ is negative

Step 1

Find the value of $sin(\theta)$

Remember

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(\theta)=1-\frac{1}{2}$

$sin^{2}(\theta)=\frac{1}{2}$

$sin(\theta)=-\frac{\sqrt{2}}{2}$ ------> remember that the value is negative

Step 2

Find the value of $tan(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{2}}{2}$

$cos(\theta)=\frac{\sqrt{2}}{2}$

substitute

$tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}$

$tan(\theta)=-1$

8 0

3 years ago

Read 2 more answers

Write each ratio in simplest terms.

scZoUnD [109]

a) 2:3

c) 4:1

e) 2:1

g) 10:1

i) 60:1

b) 24: 1

d) 8:1

f) 3:4

h) 100:1

j) 20:1

Step-by-step explanation:

a) 10:15 then divide each by 5 bc its a common denominator

c) 20:5 then divide each by 5 bc its a common denominator

e) 12:6 then divide each by 6 bc its a common denominator

g) 40:4 then divide each by 4 bc its a common denominator

i) 600:10 then divide each by 10 bc its a common denominator

b) 72:3 then divide each by 3 bc its a common denominator

d) 40:5 then divide each by 5 bc its a common denominator

f) 60:80 then divide each by 20 bc its a common denominator

h) 500:5 then divide each by 5 bc its a common denominator

j) 60:3 then divide each by 3 bc its a common denominator

5 0

2 years ago