Answer:
one real solution
no real solution
one real solution
Step-by-step explanation:
*void photo*
Assume M is the Total Money
M/6 + (1/5)(M - M/6) + $600 = M
M/6 + M/5 - M/30 + $ 600 = M
M/6 + M/5 - M/30 - M = -$600
(1/6 + 1/5 - 1/30 - 1)M = -$600
-2M/3 = -$600
2M/3 = $600
M = ($600)(3/2)
M = $900
so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)
therefore,
=(1/3)($900)
=$300
$300 is the total money he gave to his children
Answer: Option C.
Step-by-step explanation:
A function goes trough the x-axis when f(x) = 0 for some value of x.
For example, when we say that a quadratic function has no real zeros, this means that the determinant is less than zero, so the roots of the equation:
a*x^2 + b*x + c = 0
are complex roots, this means that for the function:
f(x) = y = a*x^2 + b*x + c
there is not a real number x such f(x) = 0
So the correct option is C.
They each go up by 5 :) 2+5=8 8+5=14 etc.
Answer:
Step-by-step explanation:
0 and 1, both the values of the graphs of the functions are equal at both 0 and 1