Question

20 points! Thank you :)

Answer 1

Answer:

$\Large \boxed{x=-2 \ \mathrm{and} \ x=3}$

Step-by-step explanation:

The quadratic expression is given.

$2x^2-2x-12=0$

Factor the left side of the equation.

$2(x+2)(x-3)=0$

Set the factors equal to 0.

$x+2=0$

 $x=-2$

$x-3=0$

 $x=3$

The two solutions work in the original equation. The solutions make the equation true.

Answer 2

The quadratic expression:

$2 {x}^{2} - 2x - 12$

★ By split middle term,we get

$2 {x}^{2} - 6x + 4x - 12$

$2x(x - 3) + 4( x - 3)$

$(2x + 4) (x - 3)$

$2x + 4 = 0 \: \: and \: \: x - 3 = 0$

$2 x = - 4 \: \: and \: \: x = 3$

$x = - 2 \: \: and \: \: x = 3$

Therefore , the two solution of given quadratic equations is -2 and 3.