Answer:
They can`t cross because the slopes are the same.
Since the first equation isn`t simplified, I`ll simplify it.
-x + 4y = -8
4y = x - 8
<u>y = x - 2</u>
After both are simplified, both slopes will be positive 1x. That means the lines are parallel and never cross. I`m sorry if this wasn`t much help, but that is the only answer I can think of. If there is not other option than placing a real answer, than I wouldn`t know how to solve this, sorry.
Overall, Will moved farther back in line than Amber.
Use PEMDAS.
17-(6×10÷2)+12
6×10=60 divide by 2 to get 30
now: 17-30+12
17-30=-13
-13+12=-1
For school A: 2, 2, 3, 7, 10,10,14, 17, 22
School A : 2,2,3,7,10,10,14,17,22
Part A: (2 + 3) / 2 = 5/2 = 2.5
The Median is 10
(14 + 17) / 2 = 31/2 = 15.5
The IQR Is Q3 - Q1 = 15.5 - 2.5 = 13
For School B: <span>Nope, not symmetrical. The space between the medians should be the same number.
Hope this Helps. I can explain more if you have an comments.
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