Answer:
Volume: 112 m³.
Surface area: 172 m².
Step-by-step explanation:
The volume is the base times height times length. So, the volume will be 2 * 8 * 7 = 16 * 7 = 112 m³.
The surface area is 2lw + 2lh + 2wh. l = 8; w = 7; h = 2.
2(8)(7) + 2(8)(2) + 2(7)(2) = 2 * 56 + 2 * 16 + 2 * 14 = 112 + 32 + 28 = 112 + 60 = 172 m².
Hope this helps!
Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Answer:
Step-by-step explanation:
time to cross will be the distance divided by the velocity in that direction.
a) t = d/v = 45/2.75 = 16.363636... 16.4 s
In the same time that the otter is swimming cross stream, the stream is also moving perpendicularly at its own pace.
b) d = vt = 2.5(16.36) = 40.9090... 40.9 m
As velocity is a vector, An observer on the bank would see the velocity as the vector addition of the cross stream and down stream velocities
c) v = √(2.75² + 2.5²) = 3.716517... 3.72 m/s magnitude
θ = arctan2.5/2.75 = 42.2736... 42.3° downstream of a line straight across
Answer:
x = -12
Step-by-step explanation:
Step 1: Subtract 2x from both sides
2x + 10 = -14
Step 2: Subtract 10 from both sides
2x = -24
Step 3: Divide both sides by 2
x = -12
Answer:
D
Step-by-step explanation:
We know that vector addition is scalar addition.
Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>
2v = < -2.5, 4.5>
2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >
2v-u = < 1 , 6 >
This vector is basically i + 6j which is drawn in option D
