All categories

3 years ago

NEED HELP ASAP 70 POINTS

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

Answer:

x = 24 inches

Step-by-step explanation:

We can use similar triangles to solve this problem. Put the same side of the small triangle over the same side of the large triangle

5 in 8 in

--------- = ------------

15 in x in

Using cross products

5x = 8*15

Divide by 5

5x/5 = 8*15/5

x = 8*3

x = 24 inches

Vera_Pavlovna [14]3 years ago

7 0

Look at the picture.

We have the similar triangles (AAA). Therefore the lengths of the sides are in proportion:

$\dfrac{x}{8}=\dfrac{15}{5}$

$\dfrac{x}{8}=3$ multiply both sides by 8

$\boxed{x=24\ in}$

You might be interested in

In a group of 700 people only 5% of them have red hair how many people hade red hair

Svetradugi [14.3K]

35 people have red hair. Do 700 times 0.05.

3 0

3 years ago

Simplify the following expression.

erica [24]

Answer:

B) 53x + 74

Step-by-step explanation:

(59x + 64) - (6x - 10) = 59x + 64 - 6x + 10

= 53x + 74

3 0

4 years ago

At what points will Al be producing the most equal amounts of sandwiches and salads?

Neporo4naja [7]

Answer: D, Y, X

Step-by-step explanation:

The (salad, sandwich) coordinates are as follows:

A: (0, 10)

B: (1, 8)

C: (2, 6)

D: (3, 4) MOST EQUAL AMOUNTS

E: (4, 2)

F: (5, 0)

X: (4, 8) OUTSIDE OF THE PRODUCTION LINE

Y: (1, 3) UNDER THE PRODUCTION LINE

8 0

3 years ago

Read 2 more answers

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.