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Reil [10]
2 years ago
15

What are the coefficients in the expression 5x3 + 14x2 - 2x + 6?

Mathematics
2 answers:
Lostsunrise [7]2 years ago
6 0

Answer: 5,14 and -2

Step-by-step explanation:

The coefficient  is the number next to the variable.

So this case the coefficients are 5,14 and -2

azamat2 years ago
6 0

Answer:

Step-by-step explanation:

15+28-2x+6

49-2x=

x=-49/2

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Hillary is sharing a box of candy with her friends. If there are b pieces of candy in the box being split between 5 people, whic
Inga [223]

Answer: C

Step-by-step explanation:

Basically you have your candy and you split it up, which is dividing, and give the groups of candy to your friends.

7 0
3 years ago
find the volume of the cylinder with the same radius and double the height when the radius is 5 and the height is 2​
Lostsunrise [7]

Answer:

100pi

Step-by-step explanation:

pi5^5=25pi

2*2=4

25pi*4=100pi

8 0
2 years ago
What is the answer and how did you work it out
Anna71 [15]

Answer: b

Step-by-step explanation:

10 x 10= 100

15 x 10= 150

100+150= 250

8 0
3 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
2 years ago
Help me out here please
VLD [36.1K]

Step-by-step explanation:

the answe to dis question is 2

3 0
2 years ago
Read 2 more answers
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