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Gelneren [198K]
4 years ago
13

How does resonance affect the sound of instruments?

Physics
1 answer:
Margaret [11]4 years ago
3 0

Answer: I hope i can help you today!

Explanation:

A bunch of Musical instruments have been using Resonance to make the sound louder like to amplify the instrument of their sound waves, For example- The strings that go on the Violin would be an Acoustic resonance and so is the Body of the violin cause that is where the sound waves hit to make that beautiful sound that comes out once you play the instrument!

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A vertical wall (8.7 m x 3.2 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is pa
Dominik [7]

Answer:

\phi=4344.72Nm^2/c

Explanation:

From the question we are told that:

Dimension of Wall:

 (L*B)=(8.7 m * 3.2 m)

Electric field B=210 N/C

Angle \theta =42 \textdegree North

Generally the equation for electric Flux is mathematically given by

 \phi=EAcos\theta

 \phi=210*(8.7*3.2)*cos 42

 \phi=4344.72Nm^2/c

3 0
3 years ago
Write at least 4 to 5 sentences on the different measurements that helped to calculate the speed of light. There are 3 specific
iren [92.7K]
The first experiment that was made to attempt to measure the speed of light involved detonating gunpowder by Isaac Beeckman. He declared that his experiment was inconclusive. Galileo also tried to measure the speed of light using two lanterns placed across each other. The next experiment involved planets where Ole Romer based his calculation on its movements. The final calculations were derived from different theories by different scientists including Maxwell until it ended up with the exact value for the speed of light. 
4 0
3 years ago
Read 2 more answers
A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 496 N and have a center of gravity
Mandarinka [93]

Answer: 1.09 m

Explanation:

Given

Weight of the body, W1 = 496 N

Weight of his upper legs, W2 = 199 N

Weight of his lower legs, W3 = 81.2 N

Center of gravity of the body, y1 = 1.37 m

Center of gravity of the upper legs, y2 = 0.711 m

Center of gravity of the lower legs, y3 = 0.284 m

Center of gravity relative to the floor, y(f) = ?

y(f) = (W1y1 + W2y2 + W3y3) / (W1 + W2 + W3), substituting the values, we have

y(f) = [(496 * 1.37) + (199 * 0.711) + (81.2 * 0.284)] / (496 + 199 + 81.2)

y(f) = (679.52 + 141.489 + 23.0608) / 776.2

y(f) = 844.0698 / 776.2

y(f) = 1.09 m

3 0
3 years ago
Convection is a mode of heat transfer for which types of objects? A. solids and liquids B. gases and solids C. gases only D. liq
Airida [17]

The correct answer to the question will be D). Liquids and gases.

EXPLANATION:

Convection is the type of mode of heat transfer in which there will be actual motion of particles from one part to the another part of a fluid.

In case of liquids, the particles which are present at the bottom of the container get heated up first and become lighter. The lighter particles will go up and the top heavier particles will move downward. Again the same process will be repeated. In this way, a convection cycle is produced.

For instance, heating of water.

In case of gases, same thing happens just like liquid. The air particles will be heated up first and becomes lighter. These heated particles will move upward. Due to this, an empty space will be created in that region. In order to occupy the empty space, the air will flow from another region which is at low temperature as compared to the heated region. Again, the same process will be repeated which will results into the formation of convection cycle .

Hence, convection occurs both in liquids and gases.



7 0
3 years ago
Read 2 more answers
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
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