Question

A vertical wall (8.7 m x 3.2 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is parallel to the ground and points 42o north of east. What is the electric flux through the wall

Answer 1

Answer:

$\phi=4344.72Nm^2/c$

Explanation:

From the question we are told that:

Dimension of Wall:

 $(L*B)=(8.7 m * 3.2 m)$

Electric field $B=210 N/C$

Angle $\theta =42 \textdegree North$

Generally the equation for electric Flux is mathematically given by

 $\phi=EAcos\theta$

 $\phi=210*(8.7*3.2)*cos 42$

 $\phi=4344.72Nm^2/c$