Let <em>A</em> be the amount of money that Aliya deposited in the savings account. Since <em>A</em> is half as much as money as she invested in a money market account, then the amount that she invested in the market account is <em>2A.</em>
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Express the interest that Aliya earned in terms of A. Set it equal to the amount of $297.60 and then solve for <em>A</em>.
Since the savings account gives 1.9% simple interest, the total amount of interest that she will earn from the savings account is 1.9% of A, which is equal to:
![\frac{1.9}{100}\times A](https://tex.z-dn.net/?f=%5Cfrac%7B1.9%7D%7B100%7D%5Ctimes%20A)
Since the money market account gives 3.7% simple interest, the total amount of interest that she will earn from the money market account, is 3.7% of <em>2A</em>, which is equal to:
![\frac{3.7}{100}\times2A](https://tex.z-dn.net/?f=%5Cfrac%7B3.7%7D%7B100%7D%5Ctimes2A)
Add both interests in terms of A and simplify the expression:
![\begin{gathered} \frac{1.9}{100}\times A+\frac{3.7}{100}\times2A \\ =\frac{1.9}{100}\times A+\frac{7.4}{100}\times A \\ =(\frac{1.9}{100}+\frac{7.4}{100})\times A \\ =\frac{1.9+7.4}{100}\times A \\ =\frac{9.3}{100}\times A \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B1.9%7D%7B100%7D%5Ctimes%20A%2B%5Cfrac%7B3.7%7D%7B100%7D%5Ctimes2A%20%5C%5C%20%3D%5Cfrac%7B1.9%7D%7B100%7D%5Ctimes%20A%2B%5Cfrac%7B7.4%7D%7B100%7D%5Ctimes%20A%20%5C%5C%20%3D%28%5Cfrac%7B1.9%7D%7B100%7D%2B%5Cfrac%7B7.4%7D%7B100%7D%29%5Ctimes%20A%20%5C%5C%20%3D%5Cfrac%7B1.9%2B7.4%7D%7B100%7D%5Ctimes%20A%20%5C%5C%20%3D%5Cfrac%7B9.3%7D%7B100%7D%5Ctimes%20A%20%5Cend%7Bgathered%7D)
The expression (9.3/100)*A represents the total interest after one year. Then:
![\begin{gathered} \frac{9.3}{100}\times A=297.60 \\ \Rightarrow A=\frac{100}{9.3}\times297.60 \\ \Rightarrow A=\frac{100\times297.60}{9.3} \\ \Rightarrow A=\frac{29760}{9.3} \\ \Rightarrow A=3200 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B9.3%7D%7B100%7D%5Ctimes%20A%3D297.60%20%5C%5C%20%5CRightarrow%20A%3D%5Cfrac%7B100%7D%7B9.3%7D%5Ctimes297.60%20%5C%5C%20%5CRightarrow%20A%3D%5Cfrac%7B100%5Ctimes297.60%7D%7B9.3%7D%20%5C%5C%20%5CRightarrow%20A%3D%5Cfrac%7B29760%7D%7B9.3%7D%20%5C%5C%20%5CRightarrow%20A%3D3200%20%5Cend%7Bgathered%7D)
Use the value of <em>A</em> to find the amount that was invested in the money market account:
![2A=2\times3200=6400](https://tex.z-dn.net/?f=2A%3D2%5Ctimes3200%3D6400)
Therefore, Aliya deposited 3200 in a savings account and 6400 in a money market account.
Answer:
The gauge pressure in Pascals inside a honey droplet is 416 Pa
Explanation:
Given;
diameter of the honey droplet, D = 0.1 cm
radius of the honey droplet, R = 0.05 cm = 0.0005 m
surface tension of honey, γ = 0.052 N/m
Apply Laplace's law for a spherical membrane with two surfaces
Gauge pressure = P₁ - P₀ = 2 (2γ / r)
Where;
P₀ is the atmospheric pressure
Gauge pressure = 4γ / r
Gauge pressure = 4 (0.052) / (0.0005)
Gauge pressure = 416 Pa
Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa
The sample appears to have gone through 3 half-lives
1st half life: 1000 to 500 g
2nd half life: 500 to 250 g
3rd half life: 250 to 125 g
The duration of a half-life, therefore, can be inferred to be 66 ÷ (3) = 22 days.
After a 4th half life, there will be 125÷2= 62.5 g.
At this point, an additional 22 days will have passed, for a total of 88 days.
Answer is C.
It really depends on how far or close the planet is from the sun