The correlation coefficient of the health research institute data measures the relationship between the age and the years of the smokers
The correlation coefficient is 0.53
<h3>How to calculate the correlation coefficient</h3>
The correlation coefficient (r) is calculated as:
![r = \frac{n(\sum xy) - \sum x \sum y}{\sqrt{[n \sum x^2 - (\sum x)^2][n\sum y^2 - (\sum y)^2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bn%28%5Csum%20xy%29%20-%20%5Csum%20x%20%5Csum%20y%7D%7B%5Csqrt%7B%5Bn%20%5Csum%20x%5E2%20-%20%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%20%28%5Csum%20y%29%5E2%7D%7D)
Using the given parameters, we have:
![r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1257^2][20 * 836 - 116^2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B20%20%2A8249%20-%201257%2A%20116%7D%7B%5Csqrt%7B%5B20%20%2A%2098823%20-%201257%5E2%5D%5B20%20%2A%20836%20-%20116%5E2%7D%7D)
Evaluate the exponents
![r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1580049][20 * 836 - 13456}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B20%20%2A8249%20-%201257%2A%20116%7D%7B%5Csqrt%7B%5B20%20%2A%2098823%20-%201580049%5D%5B20%20%2A%20836%20-%2013456%7D%7D)
Evaluate the products
![r = \frac{164980 - 145812}{\sqrt{[1976460 - 1580049][16720 - 13456}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B164980%20-%20145812%7D%7B%5Csqrt%7B%5B1976460%20-%201580049%5D%5B16720%20-%2013456%7D%7D)
Evaluate the differences

Evaluate the product

Evaluate the root

Evaluate the quotient

Hence, the correlation coefficient is 0.53
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Answer:
HCF of 120 and 180 is 60 and hence a measuring tin of 60 litre volume should be bought.
2, 3, 5. I just solved them and they look equivalent.
An extended proportion<span>. </span>Proportion<span>: A </span>proportion<span> is a statement that two or more ratios are equal to each other. Chap 3 Day 9 Monday 102510 Page 2 Page 3 Means Extemes Property In any true </span>proportion<span>, the product of the means is equal to the product of the extremes. Ex. Solve for x using the.</span>