Answer:
- W'(2, 14)
- X'(1, 4)
- Y'(4, 11)
Step-by-step explanation:
To translate 2 left, subtract 2 from every x-value.
To translate 6 up, add 6 to every y-value.
__
W' = W +(-2, 6) = (4-2, 8+6)
W' = (2, 14)
__
X' = X +(-2, 6) = (3-2, -2+6)
X' = (1, 4)
__
Y' = Y +(-2, 6) = (6-2, 5+6)
Y' = (4, 11)
Answer:
Option B is right
Step-by-step explanation:
We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent.
These three concur at a point called the circumcentre of the triangle.
When we draw perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistance from A and B.
When we take the point of intersection of perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short this is equidistant from all 3 vertices and hence is centre of circumcicle of triangle ABC
Answer:
Here's one way to do it
Step-by-step explanation:
1. Solve the inequality for y
5x - y > -3
-y > -5x - 3
y < 5x + 3
2. Plot a few points for the "y =" line
I chose
\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}
x
−2
−1
0
1
2
y
−7
−2
3
8
13
You should get a graph like Fig 1.
3. Draw a straight line through the points
Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.
See Fig. 2.
4. Test a point to see if it satisfies the inequality
I like to use the origin,(0,0), for easy calculating.
y < 5x + 3
0 < 0 + 3
0 < 3. TRUE.
The condition is TRUE.
Shade the side of the line that contains the point (the bottom side).
And you're done (See Fig. 3).
Answer:
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Step-by-step explanation:
hhhhhhhhhhhhhhhhhhhhhhh
i'm pretty sure the slope is zero ...
