Question

How do I solve (z+7)^2=3

Answer 1

(z+7)^2=3
z^2+14z+46=0
z={-14+-√(14^2-4.1.46)}/2.1
=-14+-√(196-184)/2
=-14+-√12/2
=-14+-2√3/2
=-7+-√3
so it is,
z=-7+√3
or,
z=-7-√3