All categories

2 years ago

How do I solve (z+7)^2=3

1 answer:

4 0

(z+7)^2=3
z^2+14z+46=0
z={-14+-√(14^2-4.1.46)}/2.1
=-14+-√(196-184)/2
=-14+-√12/2
=-14+-2√3/2
=-7+-√3
so it is,
z=-7+√3
or,
z=-7-√3

You might be interested in

Question 1) When multiplying powers with the same base, keep the base and _______________ the exponents.

nika2105 [10]

The rules are

$x^a\cdot x^b = x^{a+b}$

$\dfrac{x^a}{x^b} = x^{a-b}$

Let me show you why with a couple of examples: suppose we want to multiply

$4^3\cdot 4^2$

Since powers are just repeated multiplications, we have

$4^3\cdot 4^2 = \underbrace{4\cdot 4\cdot 4}_{4^3}\cdot\underbrace{4\cdot 4}_{4^2}=4^5 = 4^{3+2}$

Similarly, we have

$\dfrac{4^3}{4^2} = \dfrac{4\cdot 4 \cdot 4}{4\cdot 4} = 4 = 4^1 = 4^{3-2}$

8 0

2 years ago

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

BigorU [14]

If the term in the middle is 16x^2

6x^2-24x-16x^2-9x+1 =

-10x^2-33x+1

5 0

3 years ago

Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___

BaLLatris [955]

Answer: In the figure AB is about 8.4 inches and AC is about 13.05 inches.

Step-by-step explanation: We can use cosine to find the hypotenuse. $cos(40)=\frac{10}{x} \\cos(40) (x)=\frac{10}{x}(x)\\cos(40) (x) =10\\\frac{cos(40) (x)}{cos (40)} =\frac{10}{cos (40)} \\x=\frac{10}{cos(40)}$

Using a calculator x is about 13.05

Using tangent we can find the length opposite of <C

$tan(40)=\frac{x}{10} \\tan(40) (10)=\frac{x}{10}(10)\\tan(40) (10) = x$

Using a calculator x would be about 8.4

4 0

2 years ago

Read 2 more answers

Pre-algebra<br> Pls help-

Anestetic [448]

Answer: 9

Step-by-step explanation: just devide then times

5 0

1 year ago

Read 2 more answers

A bicycle normally sells for 239.99 dollars. It is now on sale for 25% off. As an employee, Baron is able to save an extra 10% o

Mekhanik [1.2K]

239.99 x 75%(75/100) ~ $180
$180 x 90%(90/100) = $162

8 0

3 years ago