When you first pick a ticket, there are 2 winning tickets and 40 total tickets. This means that there is a 2/40 chance of your ticket being a winning one. This fraction can be reduced to 1/20.
After this, there will be 1 winning ticket left and 39 total tickets. There is a 1/39 chance of the next ticket being a winning one. We multiply these two fractions together to get our answer. 1/20 * 1/39 = 1/780, so there is a 1/780 chance of having 2 winning tickets.
Answer:
The first one is most likely to happen
Step-by-step explanation:
Answer:
![\begin{array}{cc}x&y\\ \\-2&-1\\0&-2\\2&-3\\6&-5\\9&-6.5\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5C%5C%20%5C%5C-2%26-1%5C%5C0%26-2%5C%5C2%26-3%5C%5C6%26-5%5C%5C9%26-6.5%5Cend%7Barray%7D)
Step-by-step explanation:
Given:
![y=-\dfrac{1}{2}x-2](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B2%7Dx-2)
First, find y for given x:
When x = 0, then
![y=-\dfrac{1}{2}\cdot 0-2\\ \\y=-2](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%200-2%5C%5C%20%5C%5Cy%3D-2)
When x = 6, then
![y=-\dfrac{1}{2}\cdot 6-2\\ \\y=-3-2\\ \\y=-5](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%206-2%5C%5C%20%5C%5Cy%3D-3-2%5C%5C%20%5C%5Cy%3D-5)
When x = 9, then
![y=-\dfrac{1}{2}\cdot 9-2\\ \\y=-4.5-2\\ \\y=-6.5](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%209-2%5C%5C%20%5C%5Cy%3D-4.5-2%5C%5C%20%5C%5Cy%3D-6.5)
Now find x for given y:
When y = -1, then
![-1=-\dfrac{1}{2}x-2\\ \\-1+2=-\dfrac{1}{2}x\\ \\1=-\dfrac{1}{2}x\\ \\-2=x\\ \\x=-2](https://tex.z-dn.net/?f=-1%3D-%5Cdfrac%7B1%7D%7B2%7Dx-2%5C%5C%20%5C%5C-1%2B2%3D-%5Cdfrac%7B1%7D%7B2%7Dx%5C%5C%20%5C%5C1%3D-%5Cdfrac%7B1%7D%7B2%7Dx%5C%5C%20%5C%5C-2%3Dx%5C%5C%20%5C%5Cx%3D-2)
When y = -3, then
![-3=-\dfrac{1}{2}x-2\\ \\-3+2=-\dfrac{1}{2}x\\ \\-1=-\dfrac{1}{2}x\\ \\2=x\\ \\x=2](https://tex.z-dn.net/?f=-3%3D-%5Cdfrac%7B1%7D%7B2%7Dx-2%5C%5C%20%5C%5C-3%2B2%3D-%5Cdfrac%7B1%7D%7B2%7Dx%5C%5C%20%5C%5C-1%3D-%5Cdfrac%7B1%7D%7B2%7Dx%5C%5C%20%5C%5C2%3Dx%5C%5C%20%5C%5Cx%3D2)
So, the table is
![\begin{array}{cc}x&y\\ \\-2&-1\\0&-2\\2&-3\\6&-5\\9&-6.5\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5C%5C%20%5C%5C-2%26-1%5C%5C0%26-2%5C%5C2%26-3%5C%5C6%26-5%5C%5C9%26-6.5%5Cend%7Barray%7D)
Answer:
4
Step-by-step explanation:
i dont wanna explain but the answer is 4
Answer:
He should pay $2,790.7.
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.
After t years, the total amount of money is:
![T = E + P](https://tex.z-dn.net/?f=T%20%3D%20E%20%2B%20P)
In this question:
Rate of 10%, so I = 0.1.
9 months, so ![t = \frac{9}{12} = 0.75](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B9%7D%7B12%7D%20%3D%200.75)
How much should he pay for a note that will be worth $3,000 in 9 months?
We have to find P for which T = 3000. So
![T = E + P](https://tex.z-dn.net/?f=T%20%3D%20E%20%2B%20P)
![3000 = E + P](https://tex.z-dn.net/?f=3000%20%3D%20E%20%2B%20P)
![E = 3000 - P](https://tex.z-dn.net/?f=E%20%3D%203000%20-%20P)
Then
![E = P*I*t](https://tex.z-dn.net/?f=E%20%3D%20P%2AI%2At)
![3000 - P = P*0.1*0.75](https://tex.z-dn.net/?f=3000%20-%20P%20%3D%20P%2A0.1%2A0.75)
![1.075P = 3000](https://tex.z-dn.net/?f=1.075P%20%3D%203000)
![P = \frac{3000}{1.075}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B3000%7D%7B1.075%7D)
![P = 2790.7](https://tex.z-dn.net/?f=P%20%3D%202790.7)
He should pay $2,790.7.