PLEASE HELP..

Mathematics

1 answer:

grin007 [14]3 years ago

4 0

4.56/-2/1/2pi/14/2 is the answer

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Find the coordinates of the midpoint of the segment with the given pair of endpoints. J(6, 6); K(2, –4)

Levart [38]

Answer:

(4,1)

Step-by-step explanation:

let J(6,6) be x1, y1

let K(2,-4) be x2, y2

midpoint = (x1+x2)/2 , (y1+y2)/2

=(6+2)/2 ,(6-4)/2

= 8/2 ,2/2

=4, 1

3 0

2 years ago

Substitute y=-6x-3 y=-x+2

MrRissso [65]

-6x-3= -x+2
-5x=5
x=-1

4 0

2 years ago

Can someone please please help me on this algebra problem I’m stuck on answering the question?

Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

$\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}$

Answer: Midline=1

1) Amplitude

$\text{Amplitude =}2$

2) Periods

$\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}$

4) The trigonometric equation is,

$\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}$

Answer: