All categories

2 years ago

PLZ HELP ITS DUE RIGHT NOW

Mathematics

1 answer:

daser333 [38]2 years ago

4 0

Answer:

Step-by-step explanation:

Yes.

You might be interested in

Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)

Flauer [41]

Answer:

(a) 36

(b) y = 36x-31

Step-by-step explanation:

(a) dy/dx = 18x

slope of tangent at (2, 41) = 18(2)

= 36

(b) using y-y1 = m(x-x1)

y-41 = 36(x-2)

y = 36x-31

6 0

2 years ago

Rewrite using a single positive exponent. 78 73

vivado [14]

Hey! I don’t know if this is what you mean.. but I tried to understand it.

78^1
73^1

Have a good day :)

3 0

2 years ago

I need help my question is -2 less than or equal to 3x-2 <10

Kisachek [45]

A n s w e r:

0 ≤ x < 4

4 0

2 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3>Correct Question :-</h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3>Given :- </h3>

We have AP, 

$\sf{ 2 , 14 ,.... 98 }$
AP is the arithmetic progression or a sequence of numbers in which succeeding number is differ from preceeding number by a common value.

<h3>Solution :-</h3>

We have an AP :- 2 , 14 .....98

Therefore,

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

Here,

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

Now, 

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

1 year ago

How many of each type of box is it carrying?

CaHeK987 [17]

Answer:

Number of large boxes: 55

Number of small boxes:65

Step-by-step explanation:

Let be "l" the number of large boxes and "s" the number of small boxes.

Set up a system of equations:

$\left \{ {{l+s=120} \atop {60l+30s=5250}} \right.$

Use the methof of elimination. Mulitply the first equation by -60 and add both equations. Then solve for "s":

$\left \{ {{-60l-60s=-7200} \atop {60l+30s=5250}} \right.\\.........................\\-30s=-1950\\s=65$

Substitute s=65 into any of the original equations and solve for "l":

$l+65=120\\l=55$

8 0

2 years ago

Read 2 more answers