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geniusboy [140]

2 years ago

15

I need help with this is it yes or no?

1 answer:

n200080 [17]2 years ago

4 0

Answer:

No.

Step-by-step explanation:

Try the vertical line test. If the lines intersect or connect at some point, then it's not a function. Do you want to practice with some Ixls to help, or use some images for reference?

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In shop a crunchy peanut butter costs $325 for 250g

FinnZ [79.3K]

Answer:

shop b

Step-by-step explanation:

We can find for example how much 100 grams of peanut butter cost in each shop using a proportion

shop A 100 : 250 = x : 325

x = (325 * 100) / 250 = $130

shop B 100 : 340 = x : 408

x = (408 * 100)/ 340 = $120

We discovered that shop B is cheaper

5 0

2 years ago

Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s

AnnZ [28]

Answer:

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

Step-by-step explanation:

Let

x -----> the number of minutes

y ----> the total words typed

we know that

<em>Kameryn</em>

$y=75x$ -----> equation A

<em>Joe</em>

$y=60x+510$ -----> equation B

Solve the system of equations by substitution

Substitute equation A in equation B and solve for x

$75x=60x+510$

$75x-60x=510$

$15x=510$

$x=34\ minutes$

That means

For x=34 minutes

The amount of words written by Kameryn and Joe are the same.

therefore

For x > 34 minutes

Kameryn will have more words typed than Joe when the number of minutes exceeds 34.

6 0

3 years ago

What does -12x-2 equal?<br>

blsea [12.9K]

Answer:

Step-by-step explanation:-12x=2

X=-12/2

X=-6

8 0

2 years ago

Lucas was comparing the weights of boxes of crackers shown in this table. Which list shows the boxes of crackers ordered from gr

Nataly_w [17]

Wheat, Rye, Oat, and Rice

8 0

2 years ago

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

2 years ago