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White raven [17]

3 years ago

13

What is the actual distance between Saugerties and Kingston? Scale: 1 in= 2.5 mi. They are 4 in apart. What is the distance in m

iles?

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

that would be 10 miles

Step-by-step explanation:

1 = 2.5 MILES

4:x

2.5 x 4 = 10

if i am wrong please explain cause it might me being dumb or something else

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In the barn, there are horses and chickens. There are 11 heads and 32 legs altogether. How many chickens are there?

Masteriza [31]

Answer:

6 Chickens

Step-by-step explanation:

Let H represent the number of horses and C represent the number of chickens. Since there are 32 legs altogether this means that on equation to use would be given by:

2C + 4 H = 32 (Eq. 1)

Another equation can be made from the fact that there are 11 heads or 11 animals altogether which can be written as:

C + H = 11 (Eq. 2)

From Eq. 2, solve for the number of chickens:

C + H = 11

C = 11 - H (Eq. 3)

Substituting Eq. 3 in Eq. 1, the number of horses can be determined:

2 C + 4 H = 32

2 ( 11 − H ) + 4 H = 32

22 − 2 H + 4 H = 32

2H = 32 − 22

2 H = 10

H = 5 Eq.4

Putting Eq.4 in Eq.1

2C + 4*5 = 32

2C = 32 - 20

2C = 12

C = 12/2

C = 6

8 0

3 years ago

For the population of all college students currently taking a statistics course, you want to estimate the proportion who are wom

inessss [21]

Answer:

No

Step-by-step explanation:

To estimate population proportion from a sample, we must ensure that the sample data is random. Though a simple random sample of college students from a particular college was used as the sample data. However, selection of the college should have been randomized as well, a stratified random sample would have been a better sampling method whereby certain colleges are selected based on region or other criteria and then a random sample of it's statistics students selected. The sample proportion Obtian from a sample of this nature will be more representative of the population proportion of all college statistic student.

5 0

3 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

2 years ago

I can’t figure out how to use the zeros in the polynomial. Please explain

Temka [501]

Answer:

a) $P (x) = (x + 3) (x-1) (x-4)$

b) $P (x) = (2x + 5) (5x - 4) (x-6)$

c) $P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

$P (x) = (x + 3) (x-1) (x-4)$

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

$x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0$

---------------------------------------

$x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0$

--------------------------------------

$x = 6\\\\(x-6) = 0$

--------------------------------------

$P (x) = (2x + 5) (5x - 4) (x-6)$

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

$x = -3\\\\(x-3) = 0$

--------------------------------------

$x = 1\\\\(x-1) = 0$

--------------------------------------

$x = 4\\\\(x-4) = 0$

----------------------------------------

$x = -1\\\\(x + 1) = 0$

-----------------------------------------

$P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2$

8 0

3 years ago

Can someone plz help me on this thank you and please stop giving me links

Brilliant_brown [7]

Answer: 900π

Step-by-step explanation: To calculate the area of a circle, we do πr^2, where r is the radius. The radius is 30, so the answer is 900π.

Hope this helps!

4 0

3 years ago