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mrs_skeptik [129]
3 years ago
10

Tiffany sells musical instruments and equipment at Let It Rock in the mall. She earns a commission of 5% on the first $6,000, 7.

5% on the next $6,000, and 10% on sales over $12,000. Her total sales for the month are $14,640. What is Tiffany’s total commission?
Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

$800

Step-by-step explanation:

5% × 6000 = $350

14640 - 6000 = $8640

7.5% × 6000 = $450

8640 - 6000 = $2640

350 + 450 = $800

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(ab + 174)/3 <115

multiply by 3 on each side

ab + 174 < 345

subtract 174 from each side

ab < 171


248+ ab >366

subtract 248 from each side

ab> 118


Answer  118< ab < 171

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2 years ago
In the expression z-2t+49-q, what is 49 called?
ZanzabumX [31]
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Anyone know this geometry question? Will give brainiest
Dafna11 [192]
The opposite angles equal each other, so X and Z are equal
 using that we solve for x by setting them equal:

6x-60 = 2x+68

subtract 2x from each side:

4x -60 = 68

add 60 to each side:

4x = 128
 divide both sides by 4
x = 128/4
x = 32

now we know x so we can solve everything else by replacing x with 32

WY = 3x+5 = 3(32)+5 = 96+5 = 101

angle Z = 2x+68 = 2(32)+68 = 64+132

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5 0
2 years ago
In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
2 years ago
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