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PolarNik [594]
4 years ago
6

Which statement is true

Mathematics
1 answer:
ehidna [41]4 years ago
6 0
I think the answer is c.
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Helppppppppppppp. a and b partttt​
PilotLPTM [1.2K]

Answer:

a) 220.17 cm

b) 2127.12 cm²

Step-by-step explanation:

perimeter = circumference

it is the sum of the inner and the outer arc and the 2 side lines of 25.

we know a full circle has 360 degrees. but we only look at a segment of a circle of 150 out of the total of 360 degrees.

the circumference of a circle is

C = 2×pi×r

the 150 degree part is then

C = 2×pi×r×150/360 = 2×pi×r×15/36 = pi×r×15/18 =

= pi×r×5/6

the radius of the inner circle is 20.

=>

Ci = pi×20×5/6 = pi×50/3

the radius of the outer circle is 20 + 25 = 45

Co = pi×45×5/6 = pi×75/2

so, the total perimeter/ circumference is

C = Ci + Co + 25 + 25 = pi×50/3 + pi×75/2 + 50

= pi×100/6 + pi×225/6 + 50 = pi×325/6 + 50 =

= 220.17 cm

the area of the shaded shape is the area of the large circle segment minus the area of the small circle segment.

the area of a circle is

A = pi×r²

the 150 degree part is then

A = pi×r²×150/360 = pi×r²×5/12

so, for the inner circle that is

Ai = pi×20²×5/12 = pi×400×5/12 = pi×100×5/3 = pi×500/3

for the outer circle that is

Ao = pi×45²×5/12 = pi×2025×5/12 = pi×10125/12 =

= pi×3375/4

so, the total area of the shaded shape is

A = Ao - Ai = pi×3375/4 - pi×500/3 = pi×(10125-2000)/12 =

= pi×8125/12 = 2127.12 cm²

4 0
3 years ago
Find a third-degree polynomial equation with the rational coefficients that has roots -3 and 1+i
jolli1 [7]

Answer:

x³ + x² − 4x + 6 = 0

Step-by-step explanation:

Imaginary roots come in conjugate pairs.  So if 1+i is a root, then 1−i is also a root.

(x − (-3)) (x − (1+i) (x − (1−i)) = 0

(x + 3) (x² − (1+i) x − (1−i) x + (1+i) (1−i)) = 0

(x + 3) (x² − x − ix − x + ix + 1 − i²) = 0

(x + 3) (x² − 2x + 2) = 0

x (x² − 2x + 2) + 3 (x² − 2x + 2) = 0

x³ − 2x² + 2x + 3x² − 6x + 6 = 0

x³ + x² − 4x + 6 = 0

3 0
3 years ago
What dose 0.022222222 =
Setler79 [48]
The answer to the question is 0.022222222
8 0
3 years ago
Please I’ll give brainliest to someone who solves
vagabundo [1.1K]

Answer:

Step-by-step explanation:

A:all first shift workers.

4 0
3 years ago
in how many ways can the letter of word 'MONDAY' be arranged? How many of these arrangements do not begin with M? How many begin
cricket20 [7]

Step-by-step explanation:

Monday has 6 different letters.

and we have therefore 6 positions to put letters.

so, for the first position we have 6 choices.

for the second position the 5 choices, and so on.

that makes all together

6! = 6×5×4×3×2×1 = 720

ways to arrange the letters.

if the arrangements must not begin with M, we are taking one choice away for the 1st position.

we can express that as all the ways with only 5 choices for the first position, or as the total number of possibilities minus the ones that start with M.

1.

5×5×4×3×2×1 = 600

2.

6! - 1×5! = 720 - 120 = 600

now, for the possibilities that start with M but do not end with Y.

that is the same as demanding that the second position does not have a Y.

so, the first position has only one choice, and the second position has one choice less :

1×4×4×3×2×1 = 96

3 0
1 year ago
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