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Zolol [24]
3 years ago
10

Ira's collage must include a photo of himself as a baby, a toddler, an older child, and a current photo. He has four baby photos

, two toddler photos, seven older child photos, and three current photos to choose from. How many ways can Ira make his collage?
Mathematics
2 answers:
matrenka [14]3 years ago
8 0
For the answer to the question, <span>How many ways can Ira make his collage.</span> Just go ahead and multiple 4*2*7*3 = 168 

<span>It gives Ira 168 ways to assemble her pictures.
</span>I hope my answer helped you. Feel free to ask more questions. Have a nice day!
nalin [4]3 years ago
6 0
Hello there.
<span>
Ira's collage must include a photo of himself as a baby, a toddler, an older child, and a current photo. He has four baby photos, two toddler photos, seven older child photos, and three current photos to choose from. How many ways can Ira make his collage?
</span>
Answer: 168 
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Write an equation of the line in slope-intercept from?
netineya [11]

Answer:

y=-\frac{3}{2}x+2

Step-by-step explanation:

This is for the first question.

Slope-intercept is:

y=mx+b

m - slope

b - y-intercept

We are given the slope of -\frac{3}{2} and a y-intercept of 2.

Plug in the values:

y=mx+b\rightarrow\boxed{y=-\frac{3}{2}x+2}

Hope this helps.

4 0
3 years ago
Hi.
andreev551 [17]

Answer:

65

Step-by-step explanation:

40 + 5 × 5

40 + 25

65

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3 years ago
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Which of these ratios is NOT the same (not equivalent)? 12/4 12:3 4 to 1 24:6
Margaret [11]

The answer is A: 12/4.

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A number is 2 hundreds more than 355, what is the number?
tatiyna
I think it is 555??
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3 years ago
What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

4 0
2 years ago
Read 2 more answers
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