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2 years ago

Find the slope of the line through each pair of points. (9, 15)(16, 10)

Mathematics

1 answer:

RSB [31]2 years ago

4 0

Answer:

your answer would be -6/4

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I need help pleAse! This test is 75% of my grade

otez555 [7]

Slope formula:
M= y2-y1
———
X2-x1

7 0

2 years ago

The m∠P is three less than twice the measure of ∠Q. If ∠P and ∠Q are supplementary angles, find the measures of both angles.

notka56 [123]

Answer:

m∠P =119

m∠Q = 61

Step-by-step explanation:

m∠P = 2(∠Q)-3 or p=2(q)-3

supplementary angles so they combine to equal 180!

soooooo we can take

q+p=180

input what p equals and you get

q+ 2(q)-3=180

3q-3=180

3q=183

q=61

now we have what m∠Q is, so just subtract that from 180 to get m∠P

180-61=119

7 0

3 years ago

What is 36/63 in simplest form?

leonid [27]

36/63 in its simplest form is 4/7

Have a great day! =)

3 0

2 years ago

Read 2 more answers

I tried but kept getting it wrong ;-;<br>Find the area of the composite figure.

Aneli [31]

<15> and <10> add first 25 <25> and 5 add second 30 <30> and 7 add third 37 <37> and 6 <6> now add that an u get <43> thats ur answer :)

7 0

2 years ago

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

2 years ago