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daser333 [38]
3 years ago
5

How do you solve subtraction equations using models?

Mathematics
2 answers:
Sonja [21]3 years ago
8 0
You take the difference of the numbers.
Serhud [2]3 years ago
4 0
You draw as many rectangles that are the minuends - as many rectangles that equal the subtrahend. 
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The bottom of Ignacio's desktop is 74.5\,\text{cm}74.5cm74, point, 5, start text, c, m, end text from the floor. Ignacio sits in
sasho [114]

Answer:

r

Step-by-step explanation:

<u>Function Modeling</u>

The problem gives us the following conditions: The bottom of Ignacio's desktop is 74.5 cm from the floor, and the top of his legs is 49.3 cm from the floor. We know the chair where he's sitting at has a knob that raises the legs 4.8 cm per clockwise rotation r. This means that the total distance the legs are raised for r rotations is 4.8r. The total distance of his legs from the floor is then:

49.3+4.8r

This distance cannot reach or exceed 74.5 cm, thus

49.3+4.8r

Solving for r

\displaystyle r

Or, equivalently

\boxed{r

8 0
2 years ago
What is 40 x 365 / 6
Semmy [17]

Answer:

1,4600

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can y’all help me on question 20?!
Oxana [17]

Answer:

372 miles

Step-by-step explanation:

brainliest please

5 0
2 years ago
What is the solution? y = 3x - 5 <br> y = 1\3*+3
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

y = 3x - 5

y = 1/3x + 3

3x - 5 = 1/3x + 3....multiply everything by 3 to get rid of the fraction

9x - 15 = x + 9

9x - x = 9 + 15

8x = 24

x = 24/8

x = 3

y = 3x - 5

y = 3(3) - 5

y = 9 - 5

y = 4

solution is : x = 3 and y = 4...or (3,4) <==

3 0
3 years ago
Write the differential equation model that fits the given description. (a) The rate of change of the volume of a snowball (due t
miskamm [114]

Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

\frac{dV(t)}{dT} = A*V(t)^{2} \\ and V(0) = 900cm^{3}

where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to V(t)^{2}. Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

\frac{dr(t)}{dt}  = B*\sqrt{r(t)}

Here again appears a constant B for the "proportional" part. And i wrote the velocity as \frac{dr(t)}{dt} "the rate of change of the position with respect to te time".

7 0
3 years ago
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