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Aliun [14]
3 years ago
9

Need help with this

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

the answer is #4

Step-by-step explanation:

<h3>first you multiply the 3&4 witch is 12 then u keep the y and u add the 2&5 then u see that it is #4</h3>
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Please help me I promise I will mark Brainliest, I need an answer asap!!!!!!!! please hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Fin
ValentinkaMS [17]

Answer:

D

Step-by-step explanation:

To find the inverse, all we have to do is switch the x and f(x) so instead of f(x)  = 5x + 6, it becomes:

x = 5f(x) + 6

x - 6 = 5f(x)

f⁻¹(x) = (x - 6) / 5

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Simplify the following ratios:
jenyasd209 [6]
A) 3:4
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c) 3.5
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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
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ANEK [815]
Hello!

We drove a total of 504 miles in 9 hours. How I solved this equation is by dividing 504 by 9. 504 / 9 = 56, as the answer. You could also solve this just by adding how many times 9 can go into 504, but that will be longer for the same result.
Enjoy.

Brainliest please?
6 0
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Vadim26 [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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