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scoray [572]
3 years ago
12

Whats the radius and center of (x+4)^2+(y-2)^2=9

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0
I believe the center would be (-4,2) while the radius should be 3.
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murzikaleks [220]

Answer:

X=9

Step-by-step explanation:

3.5(7−x)+32=106−1.5(4x+18)

Step 1: Simplify both sides of the equation.

3.5(7−x)+32=106−1.5(4x+18)

(3.5)(7)+(3.5)(−x)+32=106+(−1.5)(4x)+(−1.5)(18)(Distribute)

24.5+−3.5x+32=106+−6x+−27

(−3.5x)+(24.5+32)=(−6x)+(106+−27)(Combine Like Terms)

−3.5x+56.5=−6x+79

−3.5x+56.5=−6x+79

Step 2: Add 6x to both sides.

−3.5x+56.5+6x=−6x+79+6x

2.5x+56.5=79

Step 3: Subtract 56.5 from both sides.

2.5x+56.5−56.5=79−56.5

2.5x=22.5

Step 4: Divide both sides by 2.5.

2.5x

2.5

=

22.5

2.5

x=9

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Step-by-step explanation:

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Is this answer correct?
BabaBlast [244]
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