Your original equation has no y-variable. It results in x = -2/3 when you solve for x which is a vertical line. Thus, if you want a line parallel to this that goes through point (- 1, - 4), you just set x equal to the x-value in that ordered pair.
Your parallel line is x = - 1.
The answer for the question shown above is: The shape of the cross section is a triangle.
The explanation is shown below:
Imagine that you have a plane that intersect the rectangular pyramid and it passes through its vertex and it is perpendicular to the base of the pyramid, when you look the cut, you will see a triangle as a cross section.
Answer:
M = 4.33885225095
Step-by-step explanation:
Area of the square ABFE = 10² = 100
M = 100 - (2P + Q)
Let’s calculate 2P + Q :
The area 2P + Q = area ΔABC + area of sector ACE + area of sector BCF
Note :
ΔABC is an equilateral triangle
m∠CBF = m∠CAE = 30°
area ΔABC = (CG × AB)÷2 = (8.660254037844×10)÷2 = 43.30127018922
CG = √(10^2 - 5^2)=8.660254037844 (Pythagorean theorem)
area of sector BCF = area ΔACE = 100π ÷ 12 = (8.333333333333)π
then
Area 2P + Q = area ΔABC + area sector ACE + area sector BCF
= 43.30127018922+(100÷12)π+(100÷12)π
= 43.30127018922+ (8.333333333333)π + (8.333333333333)π
= 95.66114774905
Conclusion:
M = 100 - (2P + Q) = 100-95.66114774905 = 4.33885225095
Answer: n=4 y=3
Step-by-step explanation:
3n - y = 9
2n + y = 11
n=4
3(4) - y = 9
12 - y = 9
y=3