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Nady [450]
3 years ago
14

What is 1230.932567 rounded to the nearest hundredths place?

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0
The answer would be 1230.93 

<span>Hope this helped :)</span>
liberstina [14]3 years ago
4 0
The answer is 1230.93

The hundredth position is 0.0<span>0
</span>So, in 1230.932567, the hundredth position is 1230.93
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Solve for x. Round to the nearest tenth, if necessary.
Ray Of Light [21]

Answer:

22.6

Step-by-step explanation:

because in this one you are using cos , adjacent/hypotenuse

24cos20

x = 22.552622899

3 0
2 years ago
A search committee is formed to find a new software engineer. (a) If 100 applicants apply for the job, how many ways are there t
vagabundo [1.1K]

These are three questions with three complete answers.

Answers:

(a) C(100,6) = 100! / [ 9! × (100 -9)! ] =

              = (100×99×98×97×96×95×94×93×92) / (9×8×7×6×5×4×3×2×1) =

              = 1,902,231,808,400

(b) C(9,6) = 9! / [ 6! * (9 - 6)! ] = 9! / [6! 3!] = (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =

          =  (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =  (9 × 8 × 7 ) / (3 × 2 × 1) = 84

(c) P(6,3) = 6! / (6 - 3)! = 6! / 3! = (6 × 5 × 4 × 3!) / 3! = 120

Step-by-step explanation:

(a) If 100 applicants apply for the job, how many ways are there to select a subset of 9 for a short list?

This is the formula for combinations: C (m,n) = m! / [n! (m - n)! ].

We will also use the formula for permutations, only as an intermediate step, to explain the solution. The formula for permutations is: P (m,n) = m! / (m - n)!

Next you will see why the final formula that you can use to solve the problem is that of combinations (because the order in which you make the list does not matter) and how you use it.

You have to select a subset of 9 candidates from a list of 100 applicants.

The first candidate may be chosen from the 100 different applicants, the second candidate may be chosen from the 99 left applicants, the third candidate from 98 applicants, and so on, which leads to:

  • 100 × 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92 possible variants.

Note that this is the permutation of 100 candidates taken from 9 in 9:

P(100,9)  = 100! (100 - 9)! = 100! / (91!) =

              = 100 × 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92 × 91! / 91! =

              = 100× 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92.

But you have to eliminate the repetitions!

Suppose that A, B, C, D, E, F, G, H, I represents the set formed by nine selected members whose names are A, B, C, D, E, F, G, H and I. So, any combination of those same names, written in different order, represents the same set (list). That means that there are 9! = 9× 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 equivalent lists.

That is why you must divide the first result (possible ways in which you can select nine candidates) by the number of ways that represent the same list for every set.

So, the conclusion is that the number of different lists of nine candidates is:

C(100,6) = 100! / [ 9! × (100 -9)! ] =

              = (100×99×98×97×96×95×94×93×92) / (9×8×7×6×5×4×3×2×1) =

              = 1,902,231,808,400

(b) If 6 of the 9 are selected for an interview, how many ways are there to pick the set of people who are interviewed? (You can assume that the short list is already decided).

Since, the short list, i.e. the  subset of 9 candidates is already decided, you will select 6 candidates to interview from 9 possible candidates.

So, your final set of candidates to interview will be the combination of 9 candidates taken from 6 in 6. The order of the names A, B, C, D, E, F, and G, is not relevant, and, therefore, the formula to use is that of combinations:

  • C (m,n) = m! / [n! (m - n)! ]

  • C(9,6) = 9! / [ 6! * (9 - 6)! ] = 9! / [6! 3!] = (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =

                   =  (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =  (9 × 8 × 7 ) / (3 × 2 × 1) = 84

(c) Based on the interview, the committee will rank the top three candidates and submit the list to their boss who will make the final decision. (You can assume that the interviewees are already decided.) How many ways are there to select the list from the 6 interviewees?

Ranking the top three candidates means that the order matters. Because it is not the same A, B, C than A, C, B, nor B, A, C, nor B, C, A, nor C, A, B, nor C, A, B.

Hence, you have to use the formula for permutations (not combinations).

The formula is: P(m,n) = m! / (m - n)!

Here, you must rank (select) 3 names, from a set (list) of 6 names, and the formula yields to:

  • P(6,3) = 6! / (6 - 3)! = 6! / 3! = (6 × 5 × 4 × 3!) / 3! = 120

4 0
2 years ago
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Reptile [31]

Step-by-step explanation:

18% compounded monthly

vs

charges 18% compounded semi-annually.

#1 is worse than #2 because...

Since the nominal rates are the same, the card with the more frequent compounding so it would have the higher effective rat.

Let's compare them!:

(1 + .18/12)^12 = 1.19562 ---> effective rate is 19.562 per annum

(1+.18/2)² = 1.1881

1.1881 has the effective rate of 18.88% per annum

(1 + /17/4)^4 = 1.18114.. --> effective rate is 18.114% per annum

18% monthly is .18 over 12 each month = 0.015/month

so every month multiply by 1.015

total cost = $607.99 * 1.01^number of months

18% semi annual = .18/2 every six months = .09 /half year

so every half year (6 months) multiply by 1.09

total cost = $607.99 * 1.09^ (number of months/6)

17% quarterly = .17/4 every 3 months = .0425 /quarter year

so every quarter year (3 months) multiply by 1.0425

total cost = $607.99 * 1.025^(number of months/3)

HOPE THIS HELPS YOU HAVE A GREAT GREAT GREAT FANTASTIC FRIDAY!

7 0
3 years ago
And for questions 4,5,6, and 7
pshichka [43]

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

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6) Corresponding angles

7) Linear pair

5 0
3 years ago
Perform the indicated operation. <br> (-10)-(-4) <br> 6 <br> -6 <br> 14 <br> -14
34kurt
-6 you subtract and keep the sign of the greater number



6 0
3 years ago
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