Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
| | | | x | - | 6
| | 3 x^2 | + | 10 x | - | 1
| | | | -x | + | 6
| | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer: 3 x^3 - 8 x^2 - 61 x + 6 Thus B:
10x^4y^4+2x^6-15y^6-3x^2y^2
Answer:
arithmetic progression problem
Answer:
Option C
Step-by-step explanation:
The first number is - 3, then we have a blank and the third number is - 1 1/8
In order for the numbers to be arranged from least to greatest, the number in the center should be greater than -3, and lesser than -1 1/8
Note that for negative numbers, the larger the constant, the smaller the number. i.e. -5 is smaller than -4.
So from the given options, the only number that is greater than -3 and lesser than -1 1/8 is - 2 1/4
So, option C gives us the correct answer to have the numbers ordered from least to greatest.
Answer:
The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
the maximum value of t(x) is greater than the maximum value of g(x)
