Answer:
The acceleration of the blocks is 0.392 m/s²
Explanation:
Lets revise the newton second low
<em>Newton's second law of motion states that an object will accelerate</em>
<em>when there is a net external force acting on the object</em>
<em>∑ force in direction of motion = mass × acceleration</em>
The system will move by same acceleration
So we will take all the forces acting on blocks to find the acceleration
<em>Assume that the system will move up the plane because the</em>
<em>weight of block B is greater than the component of wight of </em>
<em>block A</em>
At first we must distribute the mass of block A to two components :
One parallel to the plane ⇒ (m1)g sin 30°
One perpendicular to the plane ⇒ (m1)g cos 30°
<em>The forces acting in block A are:</em>
1. Tension (T) acting up in the rope
2. Frictional force (F) acting down (opposite to the direction of motion)
3. The parallel component of the weight acting down (mg sin 30)
<u><em>According to Newton Low:</em></u>
T - (m1)g sin(30) - F = (m1)a ⇒ (1), where (m1) is the mass of block A and
"a" is the acceleration of the system
<em>Block b will move up</em>
<em>The force acting on block B are:</em>
1. Tension (T) upward
2. Weight of block B (m2)g downward
<u><em>According to Newton Low:</em></u>
(m2)g - T = (m2)a ⇒ (2), where m2 is the mass of block B
Add equations (1) and (2) to eliminate the tension
(m2)g - (m1)g sin(30) - F = (m1 + m2)a ⇒ (3)
Frictional force F = μR, where R is the normal reaction on the block A
R = (m1)g cos30
F = μ (m1) cos30
μ = 0.4 , m1 = 3 , g = 9.8 m/s²
F = (0.4)(3)(9.8) cos30 = 10.184
m2 = 2.77
Substitute the vales in equation (3)
(2.77)(9.8) - (3)(9.8) sin30 - 10.184 = (3 + 2.77)a
27.146 - 14.7 - 10.184 = 5.77 a
2.262 = 5.77 a
Divide both sides by 5.77
a = 0.392 m/s²
<em>The acceleration of the blocks is 0.392 m/s²</em>
