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motikmotik
3 years ago
15

How many times farther is Proxima Centauri from the sun than is earth from the sun

Physics
2 answers:
eduard3 years ago
8 0

When I work it out, I get roughly 270 thousand times.

Aleks04 [339]3 years ago
5 0

Answer:

Of the three stars in the system, the dimmest - called Proxima Centauri - is actually the nearest star to the Sun. The two bright stars, called Alpha Centauri A and B form a close binary system; they are separated by only 23 times the Earth - Sun distance.

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Which are characteristics of a prokaryotic cell? Select three options.
horrorfan [7]

Answer:

prokaryotic cells have no nucleus but contain DNA.

I hope this helps

3 0
3 years ago
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Which of the following is an example of an electromagnetic wave? (2 points)
Maru [420]
A) red light
red lights are an example of an electromagnetic wave. visible lights are the only electromagnetic waves we can actually see on the spectrum. red, in particular has the biggest wavelength.

b) ocean waves
ocean waves are not an electromagnetic wave. in fact, it’s a mechanical wave. electromagnetic waves can travel through a vacuum, that is empty space, but mechanical waves cannot.

c) sound waves
sound waves are also not an electromagnetic wave. it’s a mechanical wave. you cannot hear electromagnetic waves.

d) earthquakes
an earthquake is also not an example of electromagnetic waves. it’s a mechanical wave.

hope this helps!
4 0
3 years ago
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do you think it is ever possible for an earthquake to occur or for a volcano to erupt in a place that is unexpected ? explain
olga2289 [7]
Yes.....The continetal plates shifting would cause either disaster...
8 0
4 years ago
The roller-coaster car shown in fig. 6-41 (h1 = 45 m, h2 = 16 m, h3 = 26 m), is dragged up to point 1 where it is released from
kirill [66]

There are many ways to solve this but I prefer to use the energy method. Calculate the potential energy using the point then from Potential Energy convert to Kinetic Energy at each points.

PE = KE

From the given points (h1 = 45, h2 = 16, h<span>3  </span>= 26)

Let’s use the formula: 

v2= sqrt[2*Gravity*h1]  where the gravity is equal to 9.81m/s2

v3= sqrt[2*Gravity*(h1 - h3 )] where the gravity is equal to 9.81m/s2

v4= sqrt[2*Gravity*(h1 – h2)] where the gravity is equal to 9.81m/s2

Solve for v2

v2= sqrt[2*Gravity*h1]      

    = √2*9.81m/s2*45m

v2= 29.71m/s

v3= sqrt[2*Gravity*(h1 - h3 )   

    =√2*9.81m/s2*(45-26)

    =√2*9.81m/s2*19 

v3=19.31m/s

v4= sqrt[2*Gravity*(h1 – h2)]        

    =√2*9.81m/s2*(45-16)

    =√2*9.81m/s2*(29)

v4=23.85m/s

7 0
3 years ago
25 POINTS !!!! PLS HELP
Yuliya22 [10]

Answer:

G

Explanation

The acceleration of gravity is constant, and = 9.8 m/s² , no matter what mass of the object is. Initial speed for both objects = 0 m/s. So, after 2 sec the objects will have the same speed and the same distance.

Answer G: speed=v, distance =d.

5 0
3 years ago
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