Let: A = adult tickets; S = student tickets
a. 498 = 5A + 3S
118 = A + S
b. S = 118 - A
498 = 5A + 3(118 - A)
498 = 5A + 354 - 3A
498 - 354 = 2A
144 = 2A
A = 72
118 = S + A
118 = 72 + S
118 - 72 = S
S = 46
c. Therefore, there were 72 adult tickets and 46 student tickets sold.
Answer:
52
Step-by-step explanation:
Part A: 6 ( 8m + 2) and 48m + 12
Part B: 48m - 48m = 12 - 12
Part C: 6 (10) = 6(10)
<h3>How to determine the expressions</h3>
1. The two expressions could be gotten thus;
6(m + 2 + 7m)
Collect like terms in the bracket
6 ( 8m + 2) ⇒ first expression
6(m + 2 + 7m)
Expand the bracket
6m + 12 + 42m
Collect like terms
6m + 42m + 12
48m + 12 ⇒ second expression
Part B:
6(m + 2 + 7m) = 48m + 2
Expand the bracket
6m + 12 + 42m = 48m + 2
Collect like terms
48m - 48m = 12 - 12
0 = 0
Part C:
Let the expression from A be 6 ( 8m + 2)
6(m + 2 + 7m) = 6 ( 8m + 2)
Let the number be m = 1
Substitute the values
6(1 + 2 + 7(1) ) = 6 (8(1) + 2)
6 ( 1 + 2 + 7) = 6 (10)
6 (10) = 6(10)
Learn more about algebraic expressions here:
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Y-3=2(x-(-1))
y-3=2x+2
y=2x+5
plug in the numbers to the point slope equation and solve
A 1.5 standard deviation above the mean is
np + 1.5 <span>√(np(1-p))
We are given with
np = 200
p = 200/n
The standard deviation is
</span><span>√200(1-200/n))
Substituting
200 + 1.5 </span>√200(1-200/n))
By inspection, if the value of n is 200, then the radical will result to the value of 1. Only by increasing the value of n greater than 200 will the radical result to a value of less than 1 and decreasing the spread of the mean.
The answer is
the minimum is 201
the maximum is infinity