Because their jobs required them to set all day.
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Answer:
B) FADH2 -- FMN of Complex I -- Fe-S of Complex II -- Q -- Fe-S of Complex III -- Cyt c -- Cyt a of Complex IV -- O2
Explanation:
FADH2 and NADH give their high energy electrons to the terminal electron acceptor molecular oxygen via an electron transport chain. As the electrons move through electron carriers of the electron transport chain, they lose their free energy. Part of the free energy of the electrons is used to pump the protons from the matrix into the intermembrane space. Therefore, part of the energy of electrons is temporarily stored in the form of a proton concentration gradient.
NADH gives its electrons to FMN of complex I while FADH2 gives its electrons to the Fe-S center of complex II. Both the complexes are oxidized by coenzyme (Q) which in turn reduces Fe-S centers of complex III. Cyt c of complex IV obtains electrons from complex III and passes them to CuA center, to heme "a" to heme "a3-CuB center" and finally to the molecular oxygen.
So, the compounds arranged with respect to the energy content of electrons in descending order are as follows: FADH2 -- FMN of Complex I -- Fe-S of Complex II -- Q -- Fe-S of Complex III -- Cyt c -- Cyt a of Complex IV -- O2.
The correct answer would be that substance A is rice, and substance B is sugar.
For substance A to be filtered out, it means that A is a water-insoluble substance and for substance B to be recoverable by evaporating off the water, it means that B is water-soluble.
Thus, A can neither be sugar nor alcohol because neither can be recovered by filtration. Also, B can neither be coffee nor alcohol because they can not be recovered as residue through evaporation of water.
Therefore, the only correct answer is that substance A is rice, and substance B is sugar because rice can be filtered out from water while the water-soluble sugar can be recovered by evaporating the water.
More about separating mixtures here: brainly.com/question/2827008
