Answer:
Step-by-step explanation:
A={26,30,32,44,48}
B={22,26,34}
A∩B=26
number of elements=1
elements in ξ are {22,24,26,28,30,32,34,36,38,40,42,44,46,48}
number of elements in ξ=14
P(A∩B)=1/14
I can't draw venn diagram but i give hint
A={30,32,44,48}+{26}
B={22,34}+{26}
A∩B={26}
If you are given $10 every 3.5 hours and you want to find the unit rate per hour, you want to solve for how much money you make every hour. You do this by dividing the $10 by the 3.5 hours, which will result in about $2.86 per hour. (This is a rounded value)
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Option A is correct as if we solve the equation We will find that the above equation can be compared to the standard quadratic equation i.e ax^2+bx+c=0
