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2 years ago

What is the value of f(0)? A. -2 B.-1 C.0 D.1

Mathematics

2 answers:

beks73 [17]2 years ago

5 0

Answer:

The answer is C

Step-by-step explanation:

ivanzaharov [21]2 years ago

5 0

Answer:

Step-by-step explanation:

f(0) means the graph of f(x) in which the value of the variable x in the function f is zero.. So, f(0) represents graph for zero value of x

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How much of 30% HCI and 45% HCI would be needed to mix and produce 50 liters of 35% HCI

VladimirAG [237]

Answer:

33 1/3 liters of 30%
16 2/3 liters of 45%

Step-by-step explanation:

Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...

0.45x +0.30(50 -x) = 0.35(50)

0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)

x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl

33 1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.

_____

<em>Comment on the solution</em>

You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...

(mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3

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2 years ago

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BabaBlast [244]

Answer:

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Step-by-step explanation:

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1 year ago

If the base is two and you have to get to 128 whats the exponet

posledela

Answer:

Step-by-step explanation:

$= 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \\ = {2}^{7} \\$

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2 years ago

There are 6 friends that want the same number of oranges and there are 300 oranges how much number of oranges would they get eac

zimovet [89]

Answer:50

Step-by-step explanation:Since there are six friends and there are 500 oranges that would be 500 divided by 6 which equals 50

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1 year ago

Hi, how's everyone doing? I need help with these exponential equations, please. Thanks! :)

Vesna [10]

Answer:

Step-by-step explanation:

1). $2^{x^{2} +2x}=\frac{1}{2}$

$2^{x^{2} +2x}=2^{-1}$

Comparing exponents on both the sides.

x² + 2x = -1

x² + 2x + 1 = 0

(x + 1)² = 0

x = -1

2). $2^{x-3}=8^{x+1}$

$2^{x-3}=(2^{3})^{x+1}$

$2^{x-3}=(2)^{3(x+1)}$

By comparing exponents,

x - 3 = 3(x + 1)

x - 3 = 3x + 3

3x - x = 3 + 3

2x = 6

x = 3

3). $\sqrt{a^{5-k}}=a^{3-k}$

$a^{\frac{5-k}{2}}=a^{3-k}$

By comparing exponents,

$\frac{5-k}{2}=3-k$

5 - k = 2(3 - k)

5 - k = 6 - 2k

2k - k = 6 - 5

k = 1

4). $3^{x+3}=27^{(2x+6)}$

$3^{x+3}=(3^3)^{2x+6}$

$3^{x+3}=(3)^{3(2x+6)}$

By comparing exponents,

x + 3 = 3(2x + 6)

x + 3 = 6x + 18

6x - x = 3 - 18

5x = - 15

x = -3

5). $5^{x-2}=1$

$5^{(x-2)}=5^{0}$

x - 2 = 0

x = 2

6 0

2 years ago