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ICE Princess25 [194]
3 years ago
15

PLEASE HELP HELP HELP HELP PLEASE PLEASE PLEASE PLEASE PLEASE

Mathematics
1 answer:
oee [108]3 years ago
5 0
Yes they are equal they both have a side that is 25 degrees
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Look at the photo pick A B C D either one explanation not needed thank you! <3
padilas [110]

Answers

A. <

Explanation

-2.875_____ <u>-</u><u>9</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8

-2.875_____-1.125

so

-2.875 < -1.1225

cause -2 is greater than -1

8 0
3 years ago
At homecoming, 125 tickets where sold. Tickets purchased for homecoming cost $20.5 without an activity card, and $15.75 with an
ale4655 [162]

Answer:

Nearly 83 students did not had activity card.

Nearly 42 students had an activity card.

Step-by-step explanation:

Total number of tickets sold at homecoming = 125

Cost of each  ticket without activity card = $20.5

Cost of each  ticket with activity card = $15.75

Total amount earned  = $2365

Let, the number of tickets sold without activity car d  = k

So, the number of tickets sold without card = (Total sold - k)

                                                                          = 125 - k

Now, according to the question:

$20.5(k) + $15.75(125 - k)  =  $2365

or, 20.5 k + 1968.5 - 15.75 k = 2365

⇒ 4.75 k = 2365 - 1968.5 = 396.5

⇒ k = \frac{396.5}{4.75 }  = 83.47

Hence, nearly 83 students did not had activity card.

So,the number of students that had activity card = 125 - 83.47 = 41.53 ~  42

Hence, nearly 42 students had an activity card.

4 0
3 years ago
Please help ASAP!!
marta [7]

Answer:

D. NM=12; mK=70°

Step-by-step explanation:

KN≈KM so they have the same 55° and then

180°-55°-55°=70° and

6*2=12

3 0
3 years ago
consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len
makkiz [27]

The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Given that,

y forms a circle of radius r

y=2\pir

r=y/2\pi

(2-y)- forms Square Side x

(2-y) = 4x

x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = \pir² + x²

Substitute the r and x values in above equation,

A(y)= y²/4\pi+(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

y/2\pi + (y-2)/8 =0

y = 2\pi/\pi+4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/\pi+4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Learn more about Area :

brainly.com/question/28642423

#SPJ4

4 0
1 year ago
Put the following equation of a line into slope-intercept form, simplifying all fractions.
svetoff [14.1K]
The answer of your question is 4x +6y = - 5

5 0
3 years ago
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