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Marat540 [252]
2 years ago
5

A life guard works for 15 hours of first aid training and 10 hours of cpr training. what is the ratio of hours cpr to first aid

training?
Mathematics
2 answers:
kolezko [41]2 years ago
5 0
It would be 10:15

hope this helps you
grigory [225]2 years ago
4 0
It would be 10:15, which can be simplified to 2:3 if you divide by 5. Hope this helps!
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Explain the difference between a well defined set and a set that is not well defined. Give examples.
yuradex [85]

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3 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

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a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

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So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

8 0
2 years ago
The question is............
irina1246 [14]
A(n,s)=(ns^2)/(4tan(180/n)), n=number of sides, s=side length

A(8,4.6)=(8*4.6^2)/(4tan22.5)

A(8,4.6)=42.32/tan22.5 m  (exact)

A(8, 4.6)≈102.17 m^2  (to nearest hundredth of a square meter)
7 0
2 years ago
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