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3 years ago

I dont understand if anybody can help me i would be happy

Mathematics

2 answers:

MAVERICK [17]3 years ago

7 0

The answer is:

(2, 3)

the user that already responded is correct : )

SCORPION-xisa [38]3 years ago

4 0

Answer:

(2, 3)

Step-by-step explanation:

<u>The rule for this dilation is:</u>

(x, y) → (x/2, y/2)

<u>Apply this rule to point B(4, 6):</u>

B(4, 6) → B'(2, 3)

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2 years ago

In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t

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3 years ago

Can someone answer these questions for me?

WITCHER [35]

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3 years ago

Here please help!!! I will really appreciate it! Thanks for helping...

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

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3 years ago

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the

MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

6 0

3 years ago

I dont understand if anybody can help me i would be happy​

I dont understand if anybody can help me i would be happy