For the derivative tests method, assume that the sphere is centered at the origin, and consider the
circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined
1
by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner
by
x2+y2+z2=r2 =⇒z= r2−(x2+y2).
Then the volume of a box with this coordinate for the corner is given by
V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),
and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the
boundary of this domain, so we need only consider critical points contained inside the domain in order
to carry this optimization out.
For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint
x2 + y2 + z2 = r2<span>. </span>
Linear pairs are when 2 lines intersect, and are adjacent angles.
The measure of a straight angle is 180 degrees, so a linear pair<span> of angles must add up to 180 degrees.
</span>
I hope my answer helped!!!
Answer:
No, you cannot have the same input for 2 different outputs
Step-by-step explanation:
Step-by-step explanation:
What are two different ways you could find the value of a? Explain these methods. A right triangle is shown. An altitude is drawn from the right angle to the opposite side to form 2 line segments with lengths 9 and 16. The length of the other 2 sides are 15 and a....done
The answer to the question is 752cm
