Question

For the following hypothetical reaction: 3A + 5B —> 3C. How many moles of C can you produce with 2 moles of A and excess B?

Answer 1

Answer:

2 mol  

Explanation:

           3A + 5B ⟶ 3C

n/mol:   2

The molar ratio is 3 mol C:3 mol A

$\text{Moles of C} = \text{2 mol A} \times \dfrac{\text{3 mol C}}{\text{3 mol A}} = \textbf{2 mol C}$