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anzhelika [568]
3 years ago
5

List an example of an organism, population, and community for a marine ecosystem?

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer:

Organism: An organism refers to a living thing that has an organised structure, can react to stimuli, reproduce, grow, adapt, and maintain homeostasis.

Example : sea worms, jellyfish, sea anemones, shellfish, squid, octopus and starfish.

Population: A population is a distinct group of individuals, whether that group comprises a nation or a group of people with a common characteristic.

Example:  Risso´s dolphin population, Bottlenose dolphin population, Killer whale population.

Community: an interacting group of various species in a common location.

Example :  1) A  group of dolphin, 2)group of sea anemones and 3) clownfish or 4) group of whales.

Marine ecosystems include: the abyssal plain, polar regions such as the Antarctic and Arctic, coral reefs, the deep sea, kelp forests, mangroves, the open ocean, rocky shores, salt marshes and sandy shores.

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How many grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water?
dlinn [17]

Answer: Option A) 83.9g

Explanation:

KCl is the chemical formula of potassium chloride.

Given that,

Amount of moles of KCl (n) = ?

Volume of KCl solution (v) = 0.75L

Concentration of KCl solution (c) = 1.5M

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.5M x 0.75L

n = 1.125 mole

Now given that,

Amount of moles of KCl (n) = 1.125

Mass of KCl in grams = ?

For molar mass of KCl, use the molar masses of:

Potassium, K = 39g;

Chlorine,Cl = 35.5g

KCl = (39g + 35.5g)

= 74.5g/mol

Since, amount of moles = mass in grams / molar mass

1.125 mole = m / 74.5g/mol

m = 1.125 mole x 74.5g/mol

m = 83.81g

Thus, 83.9 grams of KCl are needed to prepare 0.750 L of a 1.50 M solution in water

3 0
3 years ago
Explain how you would make 450 mL of a .250M NaOH solution?
Neporo4naja [7]

Answer:

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of NaOH = x

Molar mass of NaOH = 40 g/mol

Volume of the NaOH solution =  450 mL =- 0.450 L ( 1 ml = 0.450 L)

Molarity of the solution of NaOH = 0.250 M

Molarity=\frac{1.248 g}{26 g/mol\times 0.9102254 L}=0.528 mol/L

0.250 M=\frac{x}{40 g/mol\times 0.450 L}

Solving for x:

x = 4.5 g

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

4 0
4 years ago
Energy leaves the sun as light from region called the?
tino4ka555 [31]
Late answer:
Chromosphere.
4 0
3 years ago
I need some help with chemistry. Let me know if you are good at it!
tekilochka [14]

Answer:

I think im good at it i have an A in the class

Explanation:

lol

3 0
3 years ago
How many moles of CaO will be produced from 23.9 g of Ca?<br>2Ca(s) + O2(g) – 20:0(3)<br>mol​
inessss [21]

Answer:

0.6 moles of CaO will produced.

Explanation:

Given data:

Mass of calcium = 23.9 g

Moles of CaO produced = ?

Solution:

Chemical equation:

2Ca + O₂ → 2CaO

Number of moles of calcium:

Number of moles = mass/ molar mass

Number of moles = 23.9 g / 40 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of calcium and CaO.

            Ca         :          CaO

              2          :          2

            0.6         :        0.6

 0.6 moles of CaO will produced.

4 0
3 years ago
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