Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.
<h3>What is Intramolecular Aldol Condensation ? </h3>
The condensation reaction in which two ketone groups and aldehyde group in the same molecule are called Intramolecular Aldol Condensation. Intramolecular Aldol Condensation occurs in five or six membered α, β- unsaturated aldehyde or ketones are formed.
Thus from the above conclusion we can say that Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.
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Answer: nucleus
Explanation: the bigger the nucleus there more reactive the atom is
Answer:
The amount of drug left in his body at 7:00 pm is 315.7 mg.
Explanation:
First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

Where:
λ: is the decay constant = 
: is the half-life of the drug = 3.5 h
N(t): is the quantity of the drug at time t
N₀: is the initial quantity
After 90 min and before he takes the other 200 mg pill, we have:

Now, at 7:00 pm we have:

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).
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Answer:
1
Explanation:
Using the Rydberg formula as:

where,
λ is wavelength of photon
R = Rydberg's constant (1.097 × 10⁷ m⁻¹)
Z = atomic number of atom
n₁ is the initial final level and n₂ is the final energy level
For Hydrogen atom, Z= 1
n₂ = 2
Wavelength = 410.1 nm
Also,
1 nm = 10⁻⁹ m
So,
Wavelength = 410.1 × 10⁻⁹ m
Applying in the formula as:

Solving for n₁ , we get
n₁ ≅ 1