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Serggg [28]
4 years ago
14

A balloon that contains 0.75 L of a gas at 25°C is cooled to -100°C. Calculate the new volume of the balloon.

Chemistry
1 answer:
Mariana [72]4 years ago
7 0

Answer:

I think your answer is D.

{sorry if I'm wrong}

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3 examples of substance that are soluble in water?
sp2606 [1]

Answer:

salt, rocks, blah

Explanation:

8 0
3 years ago
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What enone product would you expect to obtain from intramolecular aldol condensation of 5-oxohexanal?
skelet666 [1.2K]

Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

<h3>What is Intramolecular Aldol Condensation ? </h3>

The condensation reaction in which two ketone groups and aldehyde group in the same molecule are called Intramolecular Aldol Condensation. Intramolecular Aldol Condensation occurs in five or six membered α, β- unsaturated aldehyde or ketones are formed.

Thus from the above conclusion we can say that Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

Learn more about the Aldol Condensation here: brainly.com/question/14260386

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4 0
1 year ago
How does the size of the atoms relate to how reactive it is?
pishuonlain [190]

Answer: nucleus

Explanation: the bigger the nucleus there more reactive the atom is

5 0
4 years ago
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A certain drug has a half-life in the body of 3.5h. Suppose a patient takes one 200.Mg pill at :500PM and another identical pill
tekilochka [14]

Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

λ: is the decay constant = ln(2)/t_{1/2}

t_{1/2}: is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg

Now, at 7:00 pm we have:

t = 7:00 pm - (5:00 pm + 90 min) = 30 min

N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg    

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0
3 years ago
Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit
EleoNora [17]

Answer:

1

Explanation:

Using the Rydberg formula as:

\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})

Solving for n₁ , we get

n₁ ≅ 1

3 0
4 years ago
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