The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
Paraphrase the following steps:
•Draw a line connecting the point to the center of the circle
•Construct the perpendicular bisector of that line
•Place the compass on the midpoint, adjust its length to reach the end point, and draw an arc across the circle
•Where the arc crosses the circle will be the tangent points.
The answer is £582.4. If you add £448 + 30%, then it would equal to <span>£582.</span>
Keep in mind that, the directrix is "p" distance units away from the vertex, and the focus point is also "p" distance units from the vertex but in the opposite direction, so in short the vertex is half-way between both of them.
in this case the vertex is at the origin, and the directrix 5 units above it, so that means the parabola is vertical and opening downwards, like the one in the picture below, and the focus point is 5 units the other way.