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3 years ago

I need help on this please SHOW WORK

Mathematics

1 answer:

elena-s [515]3 years ago

7 0

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SEE IMAGE PLEASE !!!

inysia [295]

Center of rhombus bisects 90°.

Sum of angles in triangle = 180°
x + x + 14 + 90 = 180
2x + 104 = 180
2 (x + 52) = 180
x = (180 ÷ 2) - 52
x = 90 - 52
x = 38°

4 0

1 year ago

Read 2 more answers

Work out the surface area of this sphere.

MrRissso [65]

Answer:

452.2 cm

Step-by-step explanation:

A = 4πr²

A = 4 (3.14) (6)²

A = 4 (3.14) (36)

A = 452.16

A = 452.2 cm (nearest tenth)

5 0

2 years ago

Please help it is my birthday !!!

Firlakuza [10]

Answer:

happy birth day to me

Step-by-step explanation:

its F was i close

5 0

2 years ago

Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

MAVERICK [17]

Answer:

$d.\:ellipse;\:3x^2+y^2+6x-6y+3=0$ .

Step-by-step explanation:

The given conic has equation;

$3x^2+y^2=9$

Divide through by 9.

$\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}$

$\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1$ .

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

$(-1,3)$

The translated ellipse has equation;

$\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1$ .

Clear the fraction;

$3(x+1)^2+(y-3)^2=9$ .

Expand;

$3(x^2+2x+1)+(y^2-6y+9)=9$ .

$3x^2+6x+3+y^2-6y+9=9$ .

Write in general form;

$3x^2+y^2+6x-6y+9-9+3=0$ .

$3x^2+y^2+6x-6y+3=0$ .

The correct choice is D

4 0

3 years ago

Read 2 more answers

State the domain of the function y=3/x

mixer [17]

$Notice \ the \ equation \ contains \ x \ in \ the \ denominator.$

$Since \ any \ denominator \ must \ not \ equal \ zero,$

$our \ domain \ is \ restricted \ to \$ x<span>≠0</span>

8 0

3 years ago