Answer:
linear polynomial
Step-by-step explanation:
as no degree is given
The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
Here's 2 (almost) equations:
m<1 = m<3
m<1 + m<2 + m<2 + m<3 = 360
I got the first one because angle 1 and 3 are on opposite sides, so they must be equal. I got the second one because 2 and (unlisted) 4 must be equal, and all of the angles added must be 360.
A. 48 ft^2
Area of a rectangle is bh
12 * 4 = 48
